What does astronomy mean?
September 11, 2021looking for someone is very good in Folklore class
September 11, 2021
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I found: ##5.9xx10^14Hz##, Cyan.
You can find the frequency ##nu## from: ##c=lambda*nu## where: ##lambda=506xx10^-9m## is the wavelength; ##c=3xx10^8m/s## is the speed of light in vacuum. So: ##nu=c/lambda=(3xx10^8)/(506xx10^-9)=5.9xx10^14Hz##
It should be Cyan (##506 nm##):
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